MATH SOLVE

4 months ago

Q:
# Which equation defines the graph of y=x^2 after it is shifted vertically 3 units down and horizontally 5 units left? A) y=(x-5)^2 - 3 B) y= (x+5)^2 - 3 c) y=(x-3)^2 - 5 D) y= (x+3)^2 - 5

Accepted Solution

A:

The answers is B because you set x+5=0 and x=-5 so that means that the graph needs to be shifted 5 units to the left because 5 is negative and to move 3 units down you just put a -3 at the end of the equation like this y=(x+5)-3