Q:

An airplane heading due east has a velocity of 210 miles per hour. A wind is blowing from the north at 38 miles per hour. What is the resultant velocity of the airplane? (Assume that east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.)

Accepted Solution

A:
Answer:The resultant velocity of the airplane is 213.41 m/s.Step-by-step explanation:Given that,Velocity of an airplane in east direction, [tex]v_1=210\ mph[/tex]Velocity of wind from the north, [tex]v_2=38\ mph[/tex]Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :[tex]v=\sqrt{v_1^2+v_2^2}[/tex][tex]v=\sqrt{(210)^2+(38)^2}[/tex]v = 213.41 m/sSo, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.